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6x^2+14x-1340=0
a = 6; b = 14; c = -1340;
Δ = b2-4ac
Δ = 142-4·6·(-1340)
Δ = 32356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32356}=\sqrt{4*8089}=\sqrt{4}*\sqrt{8089}=2\sqrt{8089}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{8089}}{2*6}=\frac{-14-2\sqrt{8089}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{8089}}{2*6}=\frac{-14+2\sqrt{8089}}{12} $
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